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\[ \frac{\pi}{2} = \left( \int_{0}^{\infty} \frac{\sin x}{\sqrt{x}} dx \right)^2 = \sum_{k=0}^{\infty} \frac{(2k)!}{2^{2k}(k!)^2} \frac{1}{2k+1} = \prod_{k=1}^{\infty} \frac{4k^2}{4k^2 - 1} \]
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