editing
approved
editing
approved
LinearRecurrence[{1, 110, -110, -1, 1}, {1, 10, 46, 1045, 5005}, 30] (* Harvey P. Dale, Aug 13 2018 *)
approved
editing
<a href="/index/Rec#order_05">Index to sequences with entries for linear recurrences with constant coefficients</a>, signature (1,110,-110,-1,1).
proposed
approved
editing
proposed
reviewed
approved
proposed
reviewed
editing
proposed
1, 10, 46, 1045, 5005, 114886, 550450, 12636361, 60544441, 1389884770, 6659338006, 152874688285, 732466636165, 16814825826526, 80564670640090, 1849477966229521, 8861381303773681, 203425761459420730, 974671378744464766, 22374984282570050725
1,2
Also positive integers y in the solutions to 3*x^2 - 7*y^2 - 3*x + 7*y = 0, the corresponding values of x being A253476.
Colin Barker, <a href="/A253477/b253477.txt">Table of n, a(n) for n = 1..980</a>
<a href="/index/Rec#order_05">Index to sequences with linear recurrences with constant coefficients</a>, signature (1,110,-110,-1,1).
a(n) = a(n-1)+110*a(n-2)-110*a(n-3)-a(n-4)+a(n-5).
G.f.: -x*(x^4+9*x^3-74*x^2+9*x+1) / ((x-1)*(x^4-110*x^2+1)).
10 is in the sequence because the 10th centered heptagonal number is 316, which is also the 15th centered triangular number.
(PARI) Vec(-x*(x^4+9*x^3-74*x^2+9*x+1)/((x-1)*(x^4-110*x^2+1)) + O(x^100))
allocated
nonn,easy
Colin Barker, Jan 02 2015
approved
editing