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A165886
a(n) = A165641(n+1)/A165641(n).
2
1, 6, 1, 60, 1, 42, 1, 120, 1, 66, 1, 5460, 1, 6, 1, 4080, 1, 798, 1, 660, 1, 138, 1, 10920, 1, 6, 1, 1740, 1, 14322, 1, 8160, 1, 6, 1, 3838380, 1, 6, 1, 54120, 1, 1806, 1, 1380, 1, 282, 1, 371280, 1, 66, 1, 3180, 1, 798, 1, 3480, 1, 354, 1, 113573460, 1, 6, 1, 16320, 1, 64722, 1, 60, 1, 4686, 1, 560403480, 1, 6
OFFSET
0,2
COMMENTS
Conjecture: a(n)/A141459(n+1) = A006519(n+1).
The conjecture is correct at least up to n<=2000. - R. J. Mathar, Jul 04 2011
LINKS
MAPLE
A001316 := proc(n) 2^A000120(n) ; end proc:
A165641 := proc(n) A091137(n)/A001316(n) ; end proc:
A165886 := proc(n) A165641(n+1)/A165641(n) ; end proc:
seq(A165886(n), n=0..60) ; # R. J. Mathar, Jul 04 2011
PROG
(PARI)
A001316(n) = 2^hammingweight(n);
A091137(n) = { my(r=1); forprime(p=2, n+1, r*=p^(n\(p-1))); (r); }; \\ From A091137
A165641(n) = (A091137(n)/A001316(n));
A165886(n) = (A165641(n+1)/A165641(n)); \\ Antti Karttunen, Dec 19 2018, after Maple-program
CROSSREFS
Sequence in context: A347211 A083837 A049213 * A339100 A344918 A174502
KEYWORD
nonn
AUTHOR
Paul Curtz, Sep 29 2009
EXTENSIONS
More terms from Antti Karttunen, Dec 19 2018
STATUS
approved