给定两点A(0,0)与B(
)可以确定一条直线,该直线的斜率为:

因此

对于在此条直线上的点C(
),可得斜率m


通用的形式为
 |
|
 |
|
 |
|
 |
(当 时)
(当 时)
|




将第一行乘2,并加到第二行


可得
=> 
将第一行乘3,并加到第二行


可得
=> 
如果你看到一个像这样的线性方程组


你可以将第一行通过移项得到

之后,你可以替换这一项到第二行,从而可得





之后,你可以将 x = 2 代替到原方程组中的任一个方程,从而解得 y = 7。通常,当原方程组中有一项单独的y时,使用这个方法更加简单。
如果你看到了一个像这样的方程组


用y来解




用x来解






消去变量x


二式相减

用y来解

消去变量y


二式相减

用x来解
