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Revision History for A373872

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Showing entries 1-10 | older changes
a(n) = Sum_{k=1..n} (-1)^(n-k) * k! * k^(n-3) * Stirling2(n,k).
(history; published version)
#19 by Michael De Vlieger at Thu Jun 20 14:46:56 EDT 2024
STATUS

reviewed

approved

#18 by Stefano Spezia at Thu Jun 20 14:26:19 EDT 2024
STATUS

proposed

reviewed

#17 by Seiichi Manyama at Thu Jun 20 12:49:41 EDT 2024
STATUS

editing

proposed

#16 by Seiichi Manyama at Thu Jun 20 12:49:19 EDT 2024
CROSSREFS
STATUS

proposed

editing

#15 by Seiichi Manyama at Thu Jun 20 12:27:21 EDT 2024
STATUS

editing

proposed

#14 by Seiichi Manyama at Thu Jun 20 12:27:08 EDT 2024
FORMULA

B(x) = Sum_{k>=0} a(k+2) * x^k/k!, satisfies: = Sum_{k>=0} k * (1 - exp(-k*x))^k.

B(x) = Sum_{k>=0} k * (1 - exp(-k*x))^k.

STATUS

proposed

editing

#13 by Seiichi Manyama at Thu Jun 20 12:23:45 EDT 2024
STATUS

editing

proposed

#12 by Seiichi Manyama at Thu Jun 20 12:14:32 EDT 2024
FORMULA

B(x) = Sum_{k>=10} k * (1 - exp(-k*x))^k.

#11 by Seiichi Manyama at Thu Jun 20 12:14:01 EDT 2024
FORMULA

E.g.f.: Sum_{k>=1} (1 - exp(-k*x))^k / k^3.B(x) = Sum_{k>=0} a(k+2) * x^k/k!, satisfies:

B(x) = Sum_{k>=0} a(k+2) * x^k/k!, satisfies:

#10 by Seiichi Manyama at Thu Jun 20 12:13:50 EDT 2024
FORMULA

E.g.f.: Sum_{k>=1} (1 - exp(-k*x))^k / k^3.B(x) = Sum_{k>=0} a(k+2) * x^k/k!, satisfies:

B(x) = Sum_{k>=1} k * (1 - exp(-k*x))^k.

STATUS

approved

editing