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CoefficientList[ Series[(-x^2 + 1)/(x^4 - 4x^2 - 2x + 1), {x, 0, 27}], x] (* or *) LinearRecurrence[{2, 4, 0, -1}, {2, 4, 15, 46}, 27] (* Robert G. Wilson v, Jul 15 2018 *)
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CoefficientList[ Series[(-x^2 + 1)/(x^4 - 4x^2 - 2x + 1), {x, 0, 27}], x] (* or *)LinearRecurrence[{2, 4, 0, -1}, {2, 4, 15, 46}, 27] (* Robert G. Wilson v, Jul 15 2018 *)
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Colin Barker, <a href="/A316726/b316726.txt">Table of n, a(n) for n = 0..1000</a>
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The number of ways to tile (with squares and rectangles) a 2 by X (n+2) strip with the upper- left and upper- right squares removed.
Each number in the sequence is the partial sum of A033505 (n starts at 0, each number add one if n is even). We can also find the recursion relation a(n) = 2*a(n-1) + 4*a(n-2) - a(n-4) for the sequence, which could can be proved by induction.
Cf. A033505 .
_Zijing Wu, _, Jul 11 2018
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