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The T(12,2) = 7 sets are {2,12}, {4,6}, {2,4,6}, {2,4,12}, {2,6,12}, {4,6,12}, {2,4,6,12}.
The T(12,2) = 7 sets are {2,12}, {4,6}, {2,4,6}, {2,4,12}, {2,6,12}, {4,6,12}, {2,4,6,12}.
allocated for Gus WisemanRegular triangle where T(n,k) is the number of finite sets of positive integers with least common multiple n and greatest common divisor k.
1, 1, 1, 1, 0, 1, 2, 1, 0, 1, 1, 0, 0, 0, 1, 7, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 4, 2, 0, 1, 0, 0, 0, 1, 2, 0, 1, 0, 0, 0, 0, 0, 1, 7, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 32, 7, 2, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0
1,7
If k divides n then T(n,k) = T(n/k,1) = A305564(n/k); otherwise T(n,k) = 0.
Triangle begins:
1
1 1
1 0 1
2 1 0 1
1 0 0 0 1
7 1 1 0 0 1
1 0 0 0 0 0 1
4 2 0 1 0 0 0 1
2 0 1 0 0 0 0 0 1
7 1 0 0 1 0 0 0 0 1
1 0 0 0 0 0 0 0 0 0 1
32 7 2 1 0 1 0 0 0 0 0 1
The T(12,2) = 7 sets are {2,12}, {4,6}, {2,4,6}, {2,4,12}, {2,6,12}, {4,6,12}, {2,4,6,12}.
Table[Length[Select[Subsets[Divisors[n]], And[GCD@@#==k, LCM@@#==n]&]], {n, 20}, {k, n}]
allocated
nonn
Gus Wiseman, Jun 05 2018
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allocated for Gus Wiseman
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