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Colin Barker, <a href="/A305292/b305292.txt">Table of n, a(n) for n = 1..1000</a>
(PARI) Vec(x*(2 + 3*x - 8*x^2 + 3*x^3 + 2*x^4)/((1 - x)*(1 - 6*x + x^2)*(1 + 6*x + x^2)) + O(x^30)) \\ Colin Barker, Jun 14 2018
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Numbers which are between k such that k-1 is a square and k+1 is a triangular number.
a(n)-1 is a square and a(n)+1 is a triangular number. It is easy to prove that there are no numbers k such that k-1 is a triangular number and k+1 is a square.
a(n)-1 is a square and a(n)+1 is a triangular number. It is easy to prove that there are no numbers k such that k-1 is a triangular number and k+1 is a square.