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isA267010 := proc(n)
if isprime(n) and modp(n, 4) = 3 then
isA266987(n) ;
else
false;
end if;
end proc: # R. J. Mathar, Aug 14 2024
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a(1)=19. The is a term because the primitive roots of 19 are 2, 3, 10, 13, 14, and 15. Their average is (2+3+10+13+14+15)/phi(18)=57/phi(18)=57/6=19/2.
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Select[4*Range[1000] + 3, PrimeQ[#] && Mean[PrimitiveRootList[#]] == #/2 &] (* Amiram Eldar, Oct 11 2021 *)
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Primes of the form p==3 (mod 4) such that the average of their primitive roots equals p/2.
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