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Revision History for A255162

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Showing entries 1-10 | older changes
Rational part of circle radii in nested circles and hexagons (see comment).
(history; published version)
#17 by N. J. A. Sloane at Sun Feb 22 23:35:53 EST 2015
STATUS

editing

approved

#16 by N. J. A. Sloane at Sun Feb 22 23:34:44 EST 2015
NAME

a(n) is the rational Rational part of circle radii in nested circles and hexagons (see comment).

STATUS

proposed

editing

Discussion
Sun Feb 22
23:35
N. J. A. Sloane: I changed the definition. The reason is that a(n) is singular (one number) but "radii" is plural (many numbers).  Is this OK?
#15 by Jon E. Schoenfield at Mon Feb 16 12:48:28 EST 2015
STATUS

editing

proposed

#14 by Jon E. Schoenfield at Mon Feb 16 12:48:26 EST 2015
COMMENTS

Inspired by Vitruvian Man But , but using hexagons instead of squares, starting with a hexagon whose sides are of length 4 (in some units). The radius of the circle is an integer in the real quadratic number field Q(sqrt(3)), namely R(n) = A(n) + B(n)*sqrt(3) with A(0)=2, A(n) = a(n), and B(0) = 1, B(n) = A255163(n). See illustrations in the links.

FORMULA

a(n) = -12*a(n-1) + 12*a(n-2).

G.f.: -2*(12*x+1) / (12*x^2 - 12*x - 1).

STATUS

proposed

editing

#13 by Kival Ngaokrajang at Mon Feb 16 05:25:21 EST 2015
STATUS

editing

proposed

#12 by Kival Ngaokrajang at Mon Feb 16 05:14:34 EST 2015
NAME

a(n) is the rational part of circle radii in nest nested circles and hexagons (see comment).

COMMENTS

Inspired by Vitruvian Man But using hexagons instead of squares. Starting , starting with a hexagon whose sides are of length of a hexagon equal to 4 (in some unit lengthunits). The radius of circle is an integer in the real quadratic number field Q(sqrt(3)), namely R(n) = A(n) + B(n)*sqrt(3) with A(0)=2, A(n) = a(n), and B(0) = 1, B(n) = A255163(n). See illustrations in the links.

STATUS

proposed

editing

Discussion
Mon Feb 16
05:25
Kival Ngaokrajang: Edited as Jon,s suggestion in A170931.
#11 by Colin Barker at Sun Feb 15 12:18:26 EST 2015
STATUS

editing

proposed

#10 by Colin Barker at Sun Feb 15 12:17:42 EST 2015
FORMULA

Conjectures from Colin Barker, Feb 15 2015: (Start)

a(n) = -12*a(n-1)+12*a(n-2).

G.f.: -2*(12*x+1) / (12*x^2-12*x-1).

(End)

STATUS

proposed

editing

#9 by Kival Ngaokrajang at Sun Feb 15 12:03:47 EST 2015
STATUS

editing

proposed

#8 by Kival Ngaokrajang at Sun Feb 15 11:55:46 EST 2015
LINKS

Kival Ngaokrajang, <a href="/A255162/a255162_2.pdf">Illustration of initial terms</a>, <a href="/A255162/a255162_1.pdf">Vitruvian Man</a>

Kival Ngaokrajang, <a href="/A255162/a255162_2.pdf">TITLE FOR LINK</a>