proposed

approved

editing

proposed

allocated for Clark KimberlingNumbers k such that A248636(k+1) = A248636(k) + 1.

1, 3, 5, 6, 9, 11, 13, 16, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 49, 52, 55, 58, 62, 65, 68, 72, 75, 79, 82, 85, 89, 92, 96, 99, 103, 106, 110, 113, 117, 120, 124, 127, 131, 135, 138, 142, 145, 149, 152, 156, 160, 163, 167, 170, 174, 178, 181, 185, 189

1,2

Clark Kimberling, <a href="/A248638/b248638.txt">Table of n, a(n) for n = 1..400</a>

(A248636(k+1) = A248636(k)) = (2, 1, 2, 1, 2, 2, 1, 1, 2, 1, 2, 1, 2, 1, 1, 2,... ), so that A248637 = (2, 4, 7, 8, 10, 12, 14, ... ) and A248638 = (1, 3, 5, 6, 9, 11, 13, ...).

z = 300; p[k_] := p[k] = Sum[(h^3/3^h), {h, 1, k}];

d = N[Table[33/8 - p[k], {k, 1, z/5}], 12]

f[n_] := f[n] = Select[Range[z], 33/8 - p[#] < 1/4^n &, 1];

u = Flatten[Table[f[n], {n, 1, z}]] (* A248636 *)

d = Differences[u]

v = Flatten[Position[d, 1]] (* A248637 *)

w = Flatten[Position[d, 2]] (* A248638 *)

Cf. A248636, A248637.

allocated

nonn,easy

Clark Kimberling, Oct 11 2014

approved

editing

allocated for Clark Kimberling

allocated

approved