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Revision History for A226644

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Showing entries 1-10 | older changes
Number of ways to express 5/n as Egyptian fractions in just three terms; i.e., 5/n = 1/x + 1/y + 1/z satisfying 1<=x<=y<=z.
(history; published version)
#15 by N. J. A. Sloane at Sat Dec 13 00:50:34 EST 2014
STATUS

reviewed

approved

#14 by Michel Marcus at Sat Dec 13 00:28:20 EST 2014
STATUS

proposed

reviewed

#13 by Jon E. Schoenfield at Fri Dec 12 22:04:15 EST 2014
STATUS

editing

proposed

#12 by Jon E. Schoenfield at Fri Dec 12 22:04:13 EST 2014
NAME

Number of ways to express 5/n as Egyptian fractions in just three terms, ; i.e.; , 5/n = 1/x + 1/y + 1/z satisfying 1<=x<=y<=z.

COMMENTS

See A073101 for the 4/n conjecture due to Erdös Erdős and Straus.

STATUS

approved

editing

#11 by Ralf Stephan at Mon Aug 19 02:56:44 EDT 2013
STATUS

editing

approved

#10 by Ralf Stephan at Mon Aug 19 02:56:33 EDT 2013
STATUS

approved

editing

#9 by Joerg Arndt at Sun Aug 18 13:01:17 EDT 2013
STATUS

proposed

approved

#8 by Robert G. Wilson v at Sun Aug 18 12:03:47 EDT 2013
STATUS

editing

proposed

#7 by Robert G. Wilson v at Sun Aug 18 12:03:37 EDT 2013
NAME

Number of ways to express 5/n as Egyptian fractions in just three terms, i.e.; 15/n = 1/x + 1/y + 1/z satisfying 1<=x<=y<=z.

CROSSREFS
#6 by Joerg Arndt at Sun Aug 18 06:18:39 EDT 2013
NAME

Number of ways to express 5/n as Egyptian fractions in just three terms, i.e.; 1/n = 1/x + 1/y + 1/z satisfying 1<=x<=y<=z.

COMMENTS

See A073101 for the 4/n conjecture due to Erdös and Straus.

MATHEMATICA

f[n_] := Length@ Solve[ 5/n == 1/x + 1/y + 1/z && 1 <= x <= y <= z, {x, y, z}, Integers]; Array[f, 70]

CROSSREFS
STATUS

approved

editing