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reviewed
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reviewed
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a(n) = (F(2*n+1)-1)^2*(F(2*n+1) + 2)/4, n>=0. See the Melham reference for a general conjecture. - Wolfdieter Lang, Aug 10 2012.
proposed
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H. Prodinger, <a href="http://www.fq.math.ca/Papers1/46_47-3/Prodinger.pdf">On a sum of Melham and its variants</a>, The Fibonacci Quart. 46/47 (2008/2009), no. 3, 207-215.
approved
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editing
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Accumulate[Fibonacci[Range[0, 40, 2]]^3] (* Harvey P. Dale, Nov 15 2023 *)
approved
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approved
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