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Revision History for A142879

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Showing entries 1-10 | older changes
a(n) = 5*a(n-3) - a(n-6) with terms 1..6 as 0, 1, 2, 5, 7, 9.
(history; published version)
#20 by Wesley Ivan Hurt at Mon May 10 00:48:06 EDT 2021
STATUS

editing

approved

#19 by Wesley Ivan Hurt at Mon May 10 00:48:01 EDT 2021
NAME

a(n) = 5a5*a(n-3) - a(n-6) with terms 1..6 as 0, 1, 2, 5, 7, 9.

STATUS

approved

editing

#18 by Harvey P. Dale at Wed Apr 06 16:01:42 EDT 2016
STATUS

editing

approved

#17 by Harvey P. Dale at Wed Apr 06 16:01:37 EDT 2016
MATHEMATICA

LinearRecurrence[{0, 0, 5, 0, 0, -1}, {0, 1, 2, 5, 7, 9}, 40] (* Harvey P. Dale, Apr 06 2016 *)

STATUS

approved

editing

#16 by Joerg Arndt at Sat Jan 30 10:09:11 EST 2016
STATUS

reviewed

approved

#15 by Michel Marcus at Sat Jan 30 09:29:31 EST 2016
STATUS

proposed

reviewed

#14 by Michel Marcus at Sat Jan 30 09:29:24 EST 2016
STATUS

editing

proposed

#13 by Michel Marcus at Sat Jan 30 09:29:09 EST 2016
FORMULA

a(n) = 2*a(n - 1) + a(n - 2) if 3 | n, a(n) = a(n - 1) + a(n - 2) if n = 1 mod 3, and a(n) = 2*a(n - 1) - a(n - 2) if n = 2 mod 3.

G.f.: x^2*(1+2*x+5*x^2+2*x^3-x^4) / (1-5*x^3+x^6). -_ _Colin Barker_, Jan 08 2013

STATUS

reviewed

editing

Discussion
Sat Jan 30
09:29
Michel Marcus: added some spaces
#12 by Joerg Arndt at Sat Jan 30 08:34:11 EST 2016
STATUS

proposed

reviewed

#11 by Colin Barker at Sat Jan 30 08:15:36 EST 2016
STATUS

editing

proposed