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Revision History for A136331

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The discriminant of the characteristic polynomial of the O+ and O- submatrix for spin 3 of the nuclear electric quadrupole Hamiltonian is a perfect square for these values.
(history; published version)
#23 by Susanna Cuyler at Sun Jul 25 02:36:45 EDT 2021
STATUS

proposed

approved

#22 by Jon E. Schoenfield at Sat Jul 24 12:07:35 EDT 2021
STATUS

editing

proposed

#21 by Jon E. Schoenfield at Sat Jul 24 12:05:04 EDT 2021
COMMENTS

Perfect square values for discriminants are used to classify the Galois group of a polynomial. The O+ discriminant component is Sqrt[sqrt(6*(x^2-3x3*x+6)] ) (used to generate these values) and for the O- discriminant Sqrt[sqrt(6*(x^2+3x3*x+6)]).

This sequence is the negative of the O+ sequence. Also, note that if 3*a[(n] ) represents the positive terms, the negative terms are generated from 3 - 3*a[(n]).

For the O- sequence , reverse the O+ sequence and change all of the signs to generate ..., -446688, -45126, -18963, -4560, -1917, -462, -195, -48, -21, -6, -3, 0, 3, 18, 45, 192, 459, 1914, 4557, 18960, 45123, 187698, 446685.

Note that the difference equation a[(n] ) generates the above sequence divided by 3 or ..., -148895, -62566, -15041, -6320, -1519, -638, -153, -64, -15, -6, -1, 0, 1, 2, 7, 16, 65, 154, 639, 1520, 6321, 15042, 148896, ...

This sequence, its reverse , and the division -by -3 form, all appear to be new.

REFERENCES

The physics reference is G. W. King, "The Asymmetric Rotor I. Calculation and Symmetry Classification of Energy Levels", Journal of Chemical Physics, Jan 1943, Volume 11, p27pp. 27-42.

FORMULA

The difference equation is a[(n]) = 11*(a[(n-2] ) - a[(n-4])) + a[(n-6] ) with a[(0])=0, a[(1])=1, a[(2])=2, a[(3])=7, a[(4])=16, a[(5])=65. The solution is for even n: a[(n]) =( 1/2) - (1/12)*(3+2*Sqrt[sqrt(6]))*(5-2*Sqrt[sqrt(6]))^(n/2) + (1/12)*(-3+2*Sqrt[sqrt(6]))*(5+2*Sqrt[sqrt(6]))^(n/2), for odd even n , a[(n]) =( 1/2) - (1/12)*(3*Sqrt[sqrt(2]) +Sqrt[ sqrt(3]))*(5-2*Sqrt[sqrt(6]))^(n/2) + (1/12)*(3*Sqrt[sqrt(2]) -Sqrt[ sqrt(3]))*(5+2*Sqrt[sqrt(6]))^(n/2) for odd n. Multiply the resultant sequence by 3 to generate the present sequence.

STATUS

approved

editing

Discussion
Sat Jul 24
12:05
Jon E. Schoenfield: In addition to the issue raised by NJAS in the Extensions, it seems to me that there's another problem here...
12:07
Jon E. Schoenfield: "The difference equation is a(n) = 11*(a(n-2) - a(n-4)) + a(n-6) with a(0)=0, a(1)=1, a(2)=2, a(3)=7, a(4)=16, a(5)=65. The solution is a(n) = 1/2 - (1/12)*(3+2*sqrt(6))*(5-2*sqrt(6))^(n/2) + (1/12)*(-3+2*sqrt(6))*(5+2*sqrt(6))^(n/2) for even n, a(n) = 1/2 - (1/12)*(3*sqrt(2) + sqrt(3))*(5-2*sqrt(6))^(n/2) + (1/12)*(3*sqrt(2) - sqrt(3))*(5+2*sqrt(6))^(n/2) for odd n. Multiply the resultant sequence by 3 to generate the present sequence."  But in the OEIS "{a(n)}" is understood to *be* the present sequence, not 1/3 of it.  Should some of the a's in that formula entry be replaced with some other letter (denoting a separate sequence)?  If so, which ones?
#20 by Michael Somos at Wed Oct 14 20:40:13 EDT 2015
STATUS

editing

approved

#19 by Michael Somos at Wed Oct 14 20:39:58 EDT 2015
FORMULA

a(-n) = A138976(-n) for all n in Z. a(n) = 3 * A129444(n+1).

PROG

(PARI) {a(n) = localmy(m); m = if( n<0, m = 1-n, n); 3*(n<0) + 3*(-1)^(n<0) * polcoeff( (x + x^2 - 5*x^3 - x^4) / ((1 - x) * (1 - 10*x^2 + x^4)) + x*O(x^m), m)} ; /* Michael Somos, Apr 05 2008 */

STATUS

approved

editing

Discussion
Wed Oct 14
20:40
Michael Somos: Light edits.
#18 by N. J. A. Sloane at Thu Oct 03 21:34:33 EDT 2013
STATUS

proposed

approved

#17 by Michael Somos at Wed Oct 02 00:26:07 EDT 2013
STATUS

editing

proposed

#16 by Michael Somos at Wed Oct 02 00:24:54 EDT 2013
COMMENTS

I am in the process of editing this entry. The old terms were as follows:

446685, 187698, 45123, 18960, 4557, 1914, 459, 192, 45, 18, 3, 0, 3, 6, 21, 48, 195, 462, 1917, 4560, 18963, 45126, 446688

-446685, -187698, -45123, -18960, -4557, -1914, -459, -192, -45, -18, -3, 0, 3, 6, 21, 48, 195, 462, 1917, 4560, 18963, 45126, 446688

Michael Somos tells me he will submit the negative terms as a new sequence, A138976. - N. J. A. Sloane, Apr 19 2008

FORMULA

G.f.: 3 * (x + x^2 - 5*x^3 - x^4) / (1 - x - 10*x^2 + 10*x^3 + x^4 - x^5). - Michael Somos , Apr 05 2008

a(-n) = A138976(n). a(n) = 3 * A129444(n+1).

EXAMPLE

G.f. = 3*x + 6*x^2 + 21*x^3 + 48*x^4 + 195*x^5 + 462*x^6 + 1917*x^7 + ...

PROG

(PARI) {a(n) = local(m); m = if( n<0, m = 1-n, n); 3*(n<0) + 3*(-1)^(n<0) * polcoeff( 3 * (x + x^2 - 5*x^3 - x^4) / ((1 - x) * (1 - 10*x^2 + x^4)) + x*O(x^m), m)} /* _Michael Somos _, Apr 05 2008 */

CROSSREFS

A138976(n) = a(-n). Also 3*A129444(n+1) = a(n).

Cf. A129444, A138976.

STATUS

proposed

editing

Discussion
Wed Oct 02
00:26
Michael Somos: Deleted outdated comment. Added more info. Fixed code for n<0. Light edits.
#15 by Jon E. Schoenfield at Wed Oct 02 00:02:04 EDT 2013
STATUS

editing

proposed

Discussion
Wed Oct 02
00:12
Michel Marcus: Mail from Neil: I see that A136331 is now in the process of being edited. Maybe you three folks could collaborate on fixing it up! I'm happy to leave it to you. Feel free to delete my old comments.
#14 by Jon E. Schoenfield at Wed Oct 02 00:01:39 EDT 2013
COMMENTS

For the O- sequence reverse the O+ sequence and change all of the signs to generate ...-446688, -45126, -18963, -4560, -1917, -462, -195, -48, -21, -6, -3, 0, 3, 18, 45, 192, 459, 1914, 4557, 18960, 45123, 187698, 446685.

Note that the difference equation a[n] generates the above sequence divided by 3 or ..., -148895, -62566, -15041, -6320, -1519, -638, -153, -64, -15, -6, -1, 0, 1, 2, 7, 16, 65, 154, 639, 1520, 6321, 15042, 148896, ...

STATUS

proposed

editing