The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A135057

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A135057

Largest semiprime whose prime factors add up to 10^n.
(history; published version)

#7 by Jon E. Schoenfield at Sun Mar 08 20:01:51 EDT 2015

STATUS

editing

approved

#6 by Jon E. Schoenfield at Sun Mar 08 20:01:48 EDT 2015

LINKS

_Lekraj Beedassy_, , Feb 11 2008, <a href="/A135057/b135057.txt">Table of n, a(n) for n = 1..37</a>

FORMULA

a(n) = A124450(n)*(10^n - A124550(n)) {= A137611(n)*A137612(n) for n>1}.

a(n) = 100^n/4-(A124049(n))^2 . - Zak Seidov, Feb 15 2008.

STATUS

approved

editing

#5 by Russ Cox at Sat Mar 31 10:26:06 EDT 2012

LINKS

_Lekraj Beedassy (blekraj(AT)yahoo.com), _, Feb 11 2008, <a href="/A135057/b135057.txt">Table of n, a(n) for n = 1..37</a>

AUTHOR

_Lekraj Beedassy (blekraj(AT)yahoo.com), _, Feb 11 2008

Discussion

Sat Mar 31

10:26

OEIS Server: https://oeis.org/edit/global/489

#4 by Russ Cox at Fri Mar 30 17:26:24 EDT 2012

FORMULA

a(n) = 100^n/4-(A124049(n))^2 - _Zak Seidov (zakseidov(AT)yahoo.com), _, Feb 15 2008.

Discussion

Fri Mar 30

17:26

OEIS Server: https://oeis.org/edit/global/139

#3 by N. J. A. Sloane at Thu Nov 11 07:34:06 EST 2010

LINKS

Lekraj Beedassy (blekraj(AT)yahoo.com), Feb 11 2008, <a href="/A135057/b135057.txt">Table of n, a(n) for n = 1..37</a>

KEYWORD

nonn,new

nonn

#2 by N. J. A. Sloane at Fri Feb 27 03:00:00 EST 2009

LINKS

Lekraj Beedassy (blekraj(AT)yahoo.com), Feb 11 2008, <a href="http://www.research.att.com/~njas/sequences/b135057.txt">Table of n, a(n) for n = 1..37</a>

KEYWORD

nonn,new

nonn

#1 by N. J. A. Sloane at Sun Jun 29 03:00:00 EDT 2008

NAME

Largest semiprime whose prime factors add up to 10^n.

DATA

25, 2491, 249919, 24993439, 2499984871, 249999996751, 24999999992431, 2499999999940951, 249999999999995239, 24999999999999996031, 2499999999999999964279, 249999999999999999946639

OFFSET

1,1

LINKS

Lekraj Beedassy (blekraj(AT)yahoo.com), Feb 11 2008, <a href="http://www.research.att.com/~njas/sequences/b135057.txt">Table of n, a(n) for n = 1..37</a>

FORMULA

a(n) = A124450(n)*(10^n - A124550(n)) {= A137611(n)*A137612(n) for n>1}

a(n) = 100^n/4-(A124049(n))^2 - Zak Seidov (zakseidov(AT)yahoo.com), Feb 15 2008.

KEYWORD

nonn

AUTHOR

Lekraj Beedassy (blekraj(AT)yahoo.com), Feb 11 2008

STATUS

approved