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Revision History for A115565

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Showing entries 1-10 | older changes
a(n) = 5*n^4 - 10*n^3 + 20*n^2 - 15*n + 11.
(history; published version)
#25 by Charles R Greathouse IV at Thu Sep 08 08:45:24 EDT 2022
PROG

(MAGMAMagma) [5*(n^2-n)^2 +15*(n^2-n) +11: n in [1..40]]; // Vincenzo Librandi, Oct 04 2011

Discussion
Thu Sep 08
08:45
OEIS Server: https://oeis.org/edit/global/2944
#24 by Charles R Greathouse IV at Sat Aug 22 11:11:08 EDT 2015
STATUS

editing

approved

#23 by Charles R Greathouse IV at Sat Aug 22 11:10:55 EDT 2015
PROG

(PARI) a(n) = 5*n^4 - 10*n^3 + 20*n^2 - 15*n + 11 \\ Charles R Greathouse IV, Aug 22 2015

STATUS

proposed

editing

#22 by Michel Marcus at Sat Aug 22 10:59:37 EDT 2015
STATUS

editing

proposed

#21 by Michel Marcus at Sat Aug 22 10:59:22 EDT 2015
PROG

(PARI) first(m)=vector(m, i, 5*i^4 - 10*i^3 + 20*i^2 - 15*i + 11) \\ Anders Hellström, Aug 22 2015

STATUS

proposed

editing

#20 by Anders Hellström at Sat Aug 22 10:47:34 EDT 2015
STATUS

editing

proposed

#19 by Anders Hellström at Sat Aug 22 10:47:23 EDT 2015
PROG

(PARI) first(m)=vector(m, i, 5*i^4 - 10*i^3 + 20*i^2 - 15*i + 11) \\ Anders Hellström, Aug 22 2015

STATUS

proposed

editing

#18 by Wesley Ivan Hurt at Sat Aug 22 10:30:05 EDT 2015
STATUS

editing

proposed

#17 by Wesley Ivan Hurt at Sat Aug 22 10:28:55 EDT 2015
NAME

a(n) = 5*n^4 - 10*n^3 + 20*n^2 - 15*n + 11.

FORMULA

G.f.: x*(11+6*x+86*x^2+6*x^3+11*x^4)/(1-x)^5. - Wesley Ivan Hurt, Aug 22 2015

MAPLE

A115565:=n->5*n^4 - 10*n^3 + 20*n^2 - 15*n + 11: seq(A115565(n), n=1..40); # Wesley Ivan Hurt, Aug 22 2015

MATHEMATICA

CoefficientList[Series[(11 + 6 x + 86 x^2 + 6 x^3 + 11 x^4)/(1 - x)^5, {x, 0, 40}], x] (* Wesley Ivan Hurt, Aug 22 2015 *)

KEYWORD

nonn,easy

STATUS

approved

editing

#16 by Ray Chandler at Fri Jul 31 18:14:40 EDT 2015
STATUS

editing

approved