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(Python)
from sympy import binomial
(Python) def a(n): return binomial(6, n) + binomial(4, n) - 5*(n==1) # Indranil Ghosh, Mar 27 2017
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(PARI) a(n) = binomial(6, n) + binomial(4, n) - 5*(n==1); \\ Indranil Ghosh, Mar 27 2017
(Python) def a(n): return binomial(6, n) + binomial(4, n) - 5*(n==1) # Indranil Ghosh, Mar 27 2017
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Number of "antiprime-digit-subclasses".
Subsets were selected from {0, 2, 4, 5, 6, 8} and {0, 3, 6, 9} digit collections.
a(n) = binomial(6,n) + binomial(4,n) for n>1 Number of "antiprime-digit-subclasses". Subsets were selected from {0, 2, 4, 5, 6, 8} and {0, 3, 6, 9} digit collections.
a(n) = binomial(6,n) + binomial(4,n) for n > 1.
Table[Binomial[6, n] + Binomial[4, n] - 5 Boole[n == 1], {n, 100}] (* Michael De Vlieger, Mar 26 2017 *)
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a[(n] ) is the number of n-subsets [n=1,2,...,10] of the 10 decimal digits from which no prime numbers can be constructed. See also A099653.
a[(n]) =C[ binomial(6, n]) +C[ binomial(4, n] ) for n>1 Number of "antiprime-digit-subclasses". Subsets were selected from {0, 2, 4, 5, 6, 8} and {0, 3, 6, 9} digit collections.
Total number of prime irrelevant subset-classes from the 1023 non-empty nonempty k-digit-subsets equals 5 + 21 + 24 + 16 + 6 + 1 = 73 = 1023 - 950. See also A099653.
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