The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A076142

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A076142

a(n) = A064097(n) - A003313(n).
(history; published version)

#16 by N. J. A. Sloane at Fri Aug 18 09:44:47 EDT 2017

STATUS

proposed

approved

#15 by Antti Karttunen at Fri Aug 18 08:50:46 EDT 2017

STATUS

editing

proposed

#14 by Antti Karttunen at Fri Aug 18 08:43:57 EDT 2017

COMMENTS

The positions where k = 0, 1, 2, ... occurs occur for the first time are 1, 23, 129, 517, 2049, 4613, 33097, 33793, ... factorized as: 1, 23, 3*43, 11*47, 3*683, 7*659, 23*1439, 47*719, ... - Antti Karttunen, Aug 18 2017

#13 by Antti Karttunen at Fri Aug 18 08:42:21 EDT 2017

LINKS

Antti Karttunen, <a href="/A076142/b076142.txt">Table of n, a(n) for n = 1..10000</a> (also based on the b-file of A003313)

CROSSREFS

Cf. A003313, A064097, A076091.

#12 by Antti Karttunen at Fri Aug 18 08:40:52 EDT 2017

COMMENTS

The positions where k=0.. occurs for the first time are 1, 23, 129, 517, 2049, 4613, 33097, 33793, ... factorized as: 1, 23, 3*43, 11*47, 3*683, 7*659, 23*1439, 47*719, ... - Antti Karttunen, Aug 18 2017

#11 by Antti Karttunen at Fri Aug 18 08:34:46 EDT 2017

LINKS

Antti Karttunen, <a href="/A076142/b076142.txt">Table of n, a(n) for n = 1..10000</a> (based on the b-file of A003313)

FORMULA

It seems that sum(k = 1, n, a(k)) * log(n)/n^2 -> c (0.006 < c < 0.01).

#10 by Antti Karttunen at Fri Aug 18 08:32:29 EDT 2017

DATA

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 2

OFFSET

1,1129

EXTENSIONS

Extended to 129 terms by Antti Karttunen, Aug 18 2017

STATUS

approved

editing

Discussion

Fri Aug 18

08:33

Antti Karttunen: To the first term > 1.

#9 by Jon E. Schoenfield at Sun Jul 12 15:43:15 EDT 2015

STATUS

editing

approved

#8 by Jon E. Schoenfield at Sun Jul 12 15:43:13 EDT 2015

FORMULA

It seems that sum(k = 1, n, a(k)) * lnlog(n)/n^2 -> c (0.006 <c < 0.01).

STATUS

approved

editing

#7 by Russ Cox at Fri Mar 30 18:39:09 EDT 2012

AUTHOR

_Benoit Cloitre (benoit7848c(AT)orange.fr), _, Oct 31 2002

Discussion

Fri Mar 30

18:39

OEIS Server: https://oeis.org/edit/global/216