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Revision History for A058895

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Showing entries 1-10 | older changes
a(n) = n^4 - n.
(history; published version)
#94 by N. J. A. Sloane at Fri Aug 16 23:09:36 EDT 2024
STATUS

proposed

approved

#93 by Jason Yuen at Fri Aug 16 22:12:14 EDT 2024
STATUS

editing

proposed

#92 by Jason Yuen at Fri Aug 16 22:12:12 EDT 2024
FORMULA

Sum_{n>=2) } 1/a(n) = A339605. - R. J. Mathar, Jan 08 2021

STATUS

approved

editing

#91 by N. J. A. Sloane at Sun Apr 28 11:08:24 EDT 2024
STATUS

proposed

approved

#90 by Jon E. Schoenfield at Fri Apr 05 19:02:00 EDT 2024
STATUS

editing

proposed

#89 by Jon E. Schoenfield at Fri Apr 05 19:01:38 EDT 2024
FORMULA

a(n) = n*(n-1)*(n^2+n+1) = A000583(n) - n = A002061(n+1) * A002378(n-1) = (n-1) * A027444(n) = -n * A024001(n).

#88 by Jon E. Schoenfield at Fri Apr 05 18:59:30 EDT 2024
FORMULA

a(n)^3 + A068601(n)^3 + A033562(n)^3 = A185065(n)^3, for n > 0. - Vincenzo Librandi, Mar 13 2012

#87 by Jon E. Schoenfield at Fri Apr 05 18:57:57 EDT 2024
FORMULA

a(n+1) = 12*A000332(n+32) + 2*A000537(n-1). - Yasser Arath Chavez Reyes, Apr 05 2024

STATUS

proposed

editing

Discussion
Fri Apr 05
18:58
Jon E. Schoenfield: Okay like this?
#86 by Yasser Arath Chavez Reyes at Fri Apr 05 18:54:13 EDT 2024
STATUS

editing

proposed

#85 by Yasser Arath Chavez Reyes at Fri Apr 05 18:53:14 EDT 2024
FORMULA

a(n+1) = 12*A000332(n+3) + 2*A000537(n). - Yasser Arath Chavez Reyes, Apr 05 2024

STATUS

approved

editing