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A036564[n_]:=If[n>5, 2^n-45, 1]; Array[A036564, 50, 5] (* _Paolo Xausa_, Dec 03 2023 or *)
LinearRecurrence[{3, -2}, {1, 19, 83}, 50] (* Paolo Xausa, Dec 03 2023 *)
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A036564[n_]:=If[n>5, 2^n-45, 1]; Array[A036564, 50, 5] (* Paolo Xausa, Dec 03 2023 *)
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(Python) a = lambda x: 2**x-45
A036564 = [1] + [a(n) for n in range(6, 40)] # Gennady Eremin, Mar 28 2022
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