STATUS
reviewed
approved
reviewed
approved
proposed
reviewed
editing
proposed
a(n) = Sum_{k=0..n} binomial(2*n, 2*k+1)*binomial(2*k+1, k)/(k+2)), , see Amdeberhan link. - Michel Marcus, Jul 29 2015
approved
editing
reviewed
approved
proposed
reviewed
editing
proposed
a(n) = n*hypergeom([1/2 - n, 1 - n], [3], 4). - Jean-François Alcover, Sep 22 2018
a := n -> n*hypergeom([1/2 - n, 1 - n], [3], 4);
seq(simplify(a(n)), n = 1..22); # Peter Luschny, Sep 05 2022
proposed
editing
editing
proposed
Tewodros Amdeberhan, Moa Apagodu, and Doron Zeilberger, <a href="http://arxiv.org/abs/1507.07660">Wilf's "Snake Oil" Method Proves an Identity in The Motzkin Triangle</a>, arXiv:1507.07660 [math.CO], 2015.