The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A014935

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Showing entries 1-10 | older changes

A014935

a(1)=1, a(n) = n*18^(n-1) + a(n-1).
(history; published version)

#19 by Joerg Arndt at Mon Feb 12 06:36:28 EST 2024

STATUS

editing

approved

#18 by Paolo P. Lava at Mon Feb 12 06:33:10 EST 2024

FORMULA

a(n) = (1/289)*(1+18^n*(17*n-1)), with n >= 1. - Paolo P. Lava, Jan 13 2009

STATUS

approved

editing

#17 by Joerg Arndt at Wed Mar 11 06:11:21 EDT 2020

STATUS

reviewed

approved

#16 by Michel Marcus at Wed Mar 11 05:17:04 EDT 2020

STATUS

proposed

reviewed

#15 by Stefano Spezia at Wed Mar 11 03:21:21 EDT 2020

STATUS

editing

proposed

#14 by Stefano Spezia at Wed Mar 11 03:21:14 EDT 2020

FORMULA

G.f.: 1x/((1 - x)*(1 - 18*x)^2). - Stefano Spezia, Mar 11 2020

STATUS

proposed

editing

#13 by Stefano Spezia at Wed Mar 11 03:10:00 EDT 2020

STATUS

editing

proposed

#12 by Stefano Spezia at Wed Mar 11 03:09:55 EDT 2020

FORMULA

G.f.: 1/((1 - x)*(1 - 18*x)^2). - Stefano Spezia, Mar 11 2020

STATUS

proposed

editing

#11 by Jinyuan Wang at Wed Mar 11 03:08:52 EDT 2020

STATUS

editing

proposed

#10 by Jinyuan Wang at Wed Mar 11 03:08:28 EDT 2020

FORMULA

a(n) = (1/289)*(1+18^n*(17*n-1)), with n >= 01. - Paolo P. Lava, Jan 13 2009

STATUS

proposed

editing

Discussion

Wed Mar 11

03:08

Jinyuan Wang: offset is 1, so n >= 1 in formula