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Inverse Euler transform of sequence has generating function Sum_{n>1} (x^F(n) - x^(2*F(n)) ) where F() are the Fibonacci numbers.
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G.f.: Product_{n>=1} 1 + q^F(n+1) = 1 + Sum_{n>=1} ( q^F(n+1) * Product_{k=1..n-1} 1 + q^F(k+1) ). - Joerg Arndt, Oct 20 2012
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