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A365211
The sum of divisors d of n such that gcd(d, n/d) is a 5-rough number (A007310).
2
1, 3, 4, 5, 6, 12, 8, 9, 10, 18, 12, 20, 14, 24, 24, 17, 18, 30, 20, 30, 32, 36, 24, 36, 31, 42, 28, 40, 30, 72, 32, 33, 48, 54, 48, 50, 38, 60, 56, 54, 42, 96, 44, 60, 60, 72, 48, 68, 57, 93, 72, 70, 54, 84, 72, 72, 80, 90, 60, 120, 62, 96, 80, 65, 84, 144, 68
OFFSET
1,2
COMMENTS
First differs from A034448 at n = 25.
The number of these divisors is A365210(n).
LINKS
FORMULA
Multiplicative with a(p^e) = 1 + p^e for p = 2 and 3, and a(p^e) = (p^(e+1)-1)/(p-1) for a prime p >= 5.
a(n) <= A000203(n), with equality if and only if n is neither divisible by 4 nor by 9.
a(n) >= A034448(n), with equality if and only if n is not divisible by a square of a prime >= 5.
a(n) = A000203(A065330(n)) * A034448(A065331(n)).
Dirichlet g.f.: (1 - 1/2^(2*s-1)) * (1 - 1/3^(2*s-1)) * zeta(s)*zeta(s-1).
Sum_{k=1..n} a(k) ~ c * n^2, where c = 91*Pi^2/1296 = 0.69300463... .
MATHEMATICA
f[p_, e_] := If[p <= 3 , 1 + p^e, (p^(e+1)-1)/(p-1)]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100]
PROG
(PARI) a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i, 1] <= 3, 1 + f[i, 1]^f[i, 2], (f[i, 1]^(f[i, 2]+1)-1)/(f[i, 1]-1))); }
KEYWORD
nonn,easy,mult
AUTHOR
Amiram Eldar, Aug 26 2023
STATUS
approved