OFFSET
1,1
COMMENTS
This is one of three sequences that partition the positive integers. In general, suppose that r, s, t are positive real numbers for which the sets {i/r: i>=1}, {j/s: j>=1}, {k/t: k>=1} are pairwise disjoint. Let a(n) be the rank of n/r when all the numbers in the three sets are jointly ranked. Define b(n) and c(n) as the ranks of n/s and n/t. It is easy to prove that
a(n)=n+[ns/r]+[nt/r],
b(n)=n+[nr/s]+[nt/s],
c(n)=n+[nr/t]+[ns/t], where [ ]=floor.
LINKS
Clark Kimberling, Table of n, a(n) for n = 1..10000
FORMULA
a(n) = 2*floor(n*r), where r = (1+sqrt(5))/2.
MATHEMATICA
PROG
(Python)
from math import isqrt
def A283233(n): return (n+isqrt(5*n**2))&-2 # Chai Wah Wu, Aug 10 2022
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Clark Kimberling, Mar 03 2017
STATUS
approved