OFFSET
1,1
COMMENTS
Obviously tau(pqs) = tau(rs^3). So we have pairs of terms of A134922.
s = 593 is the least number such that there are just two matching pairs: (593*381187517*703949, 593^3*763079633) and (593*3911429*780389, 593^3*8680337). And for s = 853693 there are as many as 3 matching pairs.
LINKS
Vladimir Letsko, Math Marathon, problem 163 (in Russian)
EXAMPLE
2 is in the sequence because for p = 11, q = 29, r = 71 we have phi(pqs)=phi(rs^3) and sigma(pqs)=sigma(rs^3).
MAPLE
is_A236255:=proc(s::prime) local f, Q, c, d, cc, p, q, r;
f:=false:c:=2*s^2+1:
cc:=(c^2-1)/2;
Q:=numtheory[divisors](cc):
for d in Q do q:=d+c:
if isprime(q) then
p:=c+cc/(q-c): if p<q then break fi:
if isprime(p) then r:=2*(p+q)-c:
if isprime(r) then f:=true:break fi fi
fi od; f end;
for i from 1 to 2500 do s:=ithprime(i):if is_A236255(s) then print(s) fi od:
CROSSREFS
KEYWORD
nonn
AUTHOR
Vladimir Letsko, Jan 21 2014
STATUS
approved