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A122528
Minimal number k such that (2k)^(2^n) + 1 is prime, but (2k)^(2^m) + 1 is composite for m < n.
1
1, 7, 17, 76, 22, 57, 137, 117, 307, 671, 412, 1279, 767, 35926, 50915, 35453, 24297, 114094, 12259, 37949, 459722
OFFSET
0,2
COMMENTS
A079706(a(n)) = 2^n which is the first occurrence of 2^n in A079706.
Corresponding primes A084712(a(n)) are {3, 197, 1336337, 284936905588473857, 197352587024076973231046657, ...}.
EXAMPLE
a(0) = 1 because (2*1)^(2^0) + 1 = 2 + 1 = 3 is prime.
a(1) = 7 because (2*7)^(2^1) + 1 = 14^2 + 1 = 197 is prime but 14 + 1 = 15 is composite.
PROG
(PARI) a(n)=for(k=1, +oo, if(ispseudoprime((2*k)^(2^n)+1), for(m=0, n-1, ispseudoprime((2*k)^(2^m)+1)&&next(2)); return(k))) \\ Jeppe Stig Nielsen, Mar 10 2018
CROSSREFS
Cf. A056993.
Sequence in context: A086870 A107693 A217717 * A123206 A035078 A359015
KEYWORD
hard,more,nonn
AUTHOR
Alexander Adamchuk, Sep 17 2006
EXTENSIONS
Definition corrected by T. D. Noe, May 14 2008
a(9) through a(16) from the extensive tables of generalized Fermat primes compiled by Yves Gallot and others. - T. D. Noe, May 14 2008
a(17)-a(20) from Jeppe Stig Nielsen, Mar 10 2018
STATUS
approved