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A092320
"Word-factorable" numbers, or numbers k that are divisible by the number of letters in the American English word(s) for k.
3
4, 6, 12, 30, 33, 36, 40, 45, 50, 54, 56, 60, 70, 81, 88, 90, 100, 112, 150, 162, 170, 200, 240, 252, 300, 304, 336, 340, 405, 406, 418, 456, 513, 525, 528, 551, 560, 567, 600, 660, 665, 666, 693, 704, 720, 748, 810, 828, 850, 858, 874, 882, 897, 910, 924, 960, 1005
OFFSET
1,1
COMMENTS
Cal Q. Leytor (obviously an alias) asked for the lowest pair of consecutive word-factorable numbers.
Lowest pair of consecutive word-factorable numbers is 405-406; next is 665-666. - Ray Chandler, Feb 16 2004
Subsequence of A002808 (composite numbers). - Ivan N. Ianakiev, Mar 01 2020
REFERENCES
Cal Q. Leytor, The Word Factor, GAMES, October 1986, page 52.
LINKS
EXAMPLE
"One hundred twelve" has 16 letters and 112=16*7, so 112 is a term.
MATHEMATICA
Select[Range[1000], Divisible[#, StringLength[StringReplace[IntegerName[#],
{"\[Hyphen]" -> "", " " -> ""}]]] &] (* Ivan N. Ianakiev, Mar 01 2020 *)
PROG
(Python)
from num2words import num2words as n2w
def letters(n): return sum(c.isalpha() for c in n2w(n).replace(" and", ""))
def ok(n): return n%letters(n) == 0
print([k for k in range(1, 1000) if ok(k)]) # Michael S. Branicky, Jan 17 2022
CROSSREFS
Sequence in context: A115076 A126259 A068570 * A375197 A056495 A351523
KEYWORD
easy,nonn,word
AUTHOR
Bryce Herdt (mathidentity(AT)aol.com), Feb 15 2004
EXTENSIONS
More terms from Ray Chandler, Feb 16 2004
STATUS
approved