OFFSET
1,1
COMMENTS
Let fp(n,k) be the decimal concatenation of prime(n), k, and fp(n-1,k) for n > 1, and fp(1,k) = 2. Then a(n) = fp(n, 1111).
No more terms up to 6300.
LINKS
Farideh Firoozbakht, On Solution of puzzle 208 .
EXAMPLE
a(1)=85 because fp(85,1111)= 211113111151111...4331111439 is prime and fp(k,1111) is composite for k< 85 (prime(85)=439).
a(3)=304 because fp(304,1111)=211113111151111...199911112003 is a prime related to prime year 2003; this prime number has 2231 digits. fp(915,1111)=211113111151111...712911117151 is a prime with 7119 digits (prime(915)=7151).
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Farideh Firoozbakht, Jun 17 2003
EXTENSIONS
Comment from Charles R Greathouse IV, Oct 12 2009
STATUS
approved