OFFSET
1,2
COMMENTS
If p|n when at least p^5|n.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
FORMULA
Sum_{n>=1} 1/a(n) = 4 - zeta(2) - zeta(3) - zeta(4) + Sum_{k>=2} mu(k)*(4 - zeta(k) - zeta(2*k) - zeta(3*k) - zeta(4*k)) = 1.06932853458... . - Amiram Eldar, Dec 03 2022
MATHEMATICA
a = {1}; Do[ If[ Apply[ GCD, Last[ Transpose[ FactorInteger[n]]]] > 4, a = Append[a, n]; Print[n]], {n, 2, 537823}]; a
PROG
(Python)
from sympy import mobius, integer_nthroot
def A076469(n):
def f(x): return int(n+3+x-(integer_nthroot(x, 6)[0]<<1)-integer_nthroot(x, 8)[0]-integer_nthroot(x, 9)[0]-integer_nthroot(x, 12)[0]+sum(mobius(k)*(integer_nthroot(x, k)[0]+integer_nthroot(x, k<<1)[0]+integer_nthroot(x, 3*k)[0]+integer_nthroot(x, k<<2)[0]-4) for k in range(5, x.bit_length())))
kmin, kmax = 1, 2
while f(kmax) >= kmax:
kmax <<= 1
while True:
kmid = kmax+kmin>>1
if f(kmid) < kmid:
kmax = kmid
else:
kmin = kmid
if kmax-kmin <= 1:
break
return kmax # Chai Wah Wu, Aug 14 2024
CROSSREFS
KEYWORD
nonn
AUTHOR
Robert G. Wilson v, Oct 14 2002
STATUS
approved