OFFSET
1,2
COMMENTS
Consider the infinite digits: 121212... . We can break this into a sequence of integers such that the sum of digits in the n-th value is n. - Seiichi Manyama, Oct 31 2018
LINKS
Seiichi Manyama, Table of n, a(n) for n = 1..1500
FORMULA
Conjectures from Chai Wah Wu, Apr 18 2024: (Start)
a(n) = 101*a(n-3) - 100*a(n-6) for n > 6.
G.f.: x*(10*x^4 + 20*x^3 + 12*x^2 + 2*x + 1)/(100*x^6 - 101*x^3 + 1). (End)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
EXTENSIONS
More terms from Seiichi Manyama, Oct 31 2018
STATUS
approved