OFFSET
1,2
COMMENTS
Whenever a term ends in 0, then a(n+1) = a(n) + 1 is also a term. Like the other single-digit terms, zero would satisfy the definition (n = Sum_{i=1..k} d[i]^k when d[1..k] are the base-8 digits of n), but here only positive numbers are considered. - M. F. Hasler, Nov 18 2019
LINKS
Joseph Myers, Table of n, a(n) for n = 1..62 (the full list of terms, from Winter)
Gordon L. Miller and Mary T. Whalen, Armstrong Numbers: 153 = 1^3 + 5^3 + 3^3, Fibonacci Quarterly, 30-3 (1992), 221-224.
Eric Weisstein's World of Mathematics, Narcissistic Number
D. T. Winter, Table of Armstrong Numbers (latest backup on web.archive.org from Jan. 2010; page no longer available), published not later than Aug. 2003.
EXAMPLE
432 = 660_8 (= 6*8^2 + 6*8^1 + 0*8^0), and 6^3 + 6^3 + 0^3 = 432, therefore 660 is in the sequence. It's easy to see that 432 + 1 then also satisfies the equation, as for any term that is a multiple of 8. - M. F. Hasler, Nov 21 2019
PROG
(PARI) [fromdigits(digits(n, 8))|n<-A010354] \\ M. F. Hasler, Nov 18 2019
CROSSREFS
KEYWORD
base,fini,full,nonn
AUTHOR
EXTENSIONS
Edited by Joseph Myers, Jun 28 2009
STATUS
approved