algorithms/cpp/maximumSubArray/maximumSubArray.cpp

// Source : https://oj.leetcode.com/problems/maximum-subarray/
// Author : Hao Chen
// Date   : 2014-06-20

/********************************************************************************** 
* 
* Find the contiguous subarray within an array (containing at least one number) 
* which has the largest sum.
* 
* For example, given the array [&minus;2,1,&minus;3,4,&minus;1,2,1,&minus;5,4],
* the contiguous subarray [4,&minus;1,2,1] has the largest sum = 6.
* 
* More practice:
* 
* If you have figured out the O(n) solution, try coding another solution using 
* the divide and conquer approach, which is more subtle.
* 
*               
**********************************************************************************/

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define INT_MIN     (-2147483647 - 1)

int maxSubArray1(int A[], int n);
int maxSubArray2(int A[], int n); 

int max(int x, int y){
    return x>y?x:y;
}

int maxSubArray(int A[], int n) {
    if (random()%2){
        return maxSubArray1(A, n);
    }
    return maxSubArray2(A, n);
}

int maxSubArray1(int A[], int n) {
    int *sum = new int[n];
    sum[0] = A[0];
    int m = A[0]; 
    for (int i=1; i<n; i++){
        sum[i] = max(A[i], A[i] + sum[i-1]);
        m = max(m, sum[i]);
    }
    delete[] sum;
    return m;
}

int maxSubArray2(int A[], int n) {
    int m=INT_MIN;
    int sum=0;
    for (int i=0; i<n; i++){
        sum += A[i];
        m = max(sum, m);
        if (sum<0){
            sum = 0;
        }
    }
    return m;
}

int main()
{
    srand(time(NULL));
    int a[]= {-2,1,-3,4,-1,2,1,-5,4};
    printf("%d\n", maxSubArray(a, sizeof(a)/sizeof(int)));
    printf("%d\n", maxSubArray(a, sizeof(a)/sizeof(int)));
    return 0;
}