Hi,
Sorry for the delay, this is the last message that appears in console, with the same error:
16:41:40.027 request_id=F3Og_no1gcB0qXgAAxEx [warning] Failed to send Sentry event. Unable to encode JSON Sentry error - %Protocol.UndefinedError{protocol: Jason.Encoder, value: %Plausible.Ingestion.Request{id: nil, remote_ip: "172.20.0.1", user_agent: "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/16.5.2 Mobile/15E148 Safari/604.1", event_name: "pageview", uri: %URI{scheme: "https", authority: "www.domain.local", userinfo: nil, host: "www.domain.local", port: 443, path: "/es/", query: nil, fragment: nil}, hostname: "www.domain.local", referrer: "https://another.domain.local/", domains: ["www.domain.local"], hash_mode: nil, pathname: "/es/", props: %{}, query_params: nil, timestamp: ~N[2023-07-20 16:41:40]}, description: "Jason.Encoder protocol must always be explicitly implemented.\n\nIf you own the struct, you can derive the implementation specifying which fields should be encoded to JSON:\n\n @derive {Jason.Encoder, only: [....]}\n defstruct ...\n\nIt is also possible to encode all fields, although this should be used carefully to avoid accidentally leaking private information when new fields are added:\n\n @derive Jason.Encoder\n defstruct ...\n\nFinally, if you don't own the struct you want to encode to JSON, you may use Protocol.derive/3 placed outside of any module:\n\n Protocol.derive(Jason.Encoder, NameOfTheStruct, only: [...])\n Protocol.derive(Jason.Encoder, NameOfTheStruct)\n"}

Regards,

@jsarola thank you! Seems like the error is caused by adding Request struct to Sentry context here

@aerosol @vinibrsl should we inspect(request) or implement a Jason encoder for %Request{}? Otherwise no errors can be reported for this controller action.

Quickfix with inspect #3180

JSON encoder would be the best, otherwise there's not much in sentry it seems.