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python3 solution
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‎py3_solution/exercises_2.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Ask the user for a number.
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Depending on whether the number is even or odd, print out an appropriate message to the user.
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Hint: how does an even / odd number react differently when divided by 2?
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Extras:
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If the number is a multiple of 4, print out a different message.
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Ask the user for two numbers: one number to check (call it num) and one number to divide by (check).
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If check divides evenly into num, tell that to the user. If not, print a different appropriate message.
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'''
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n = input('Please input a number: ')
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n = int(n)
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if n % 2 == 0:
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print('The number you input is even')
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else:
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print('The number you input is odd')
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if n % 4 == 0:
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print('and the number is a multiple of 4')
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print('Check if a number could be divided evenly by another one: ')
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num = input('Please input a number to check: ')
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divider = input('Please input a divider number: ')
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num = int(num)
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divider = int(divider)
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remainder = num % divider
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if remainder == 0:
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print('{0} could be divided by {1} evenly'.format(num, divider))
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else:
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print('{0} could not be divided by {1} evenly, the remainder is {2}'.format(num, divider, remainder))

‎py3_solution/exercises_3.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Take a list, say for example this one:
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a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
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and write a program that prints out all the elements of the list that are less than 5.
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Extras:
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- Instead of printing the elements one by one,
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make a new list that has all the elements less than 5 from this list in it and print out this new list.
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- Write this in one line of Python.
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- Ask the user for a number and return a list that contains only elements from the original list that are smaller than the number given by the user.
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'''
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numbers = input('Please input a group of numbers seperated by ",": ')
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number_list = [int(number.strip()) for number in numbers.split(',')]
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print('Those are numbers in the group smaller than 5: ')
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for number in number_list:
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if number < 5:
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print(number)
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##########################
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# For Extras:
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##########################
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print('Filter numbers smaller than 5 to a new list: ')
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# Method 1:
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new_number_list = [number for number in number_list if number<5]
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print('filter list in Method 1: ', list(new_number_list))
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# Method 2:
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new_number_list2 = filter(lambda x:x<5, number_list)
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print('filter list in Method 2: ', list(new_number_list2))
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ceiling = input('Please input a custom filter number: ')
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ceiling = int(ceiling)
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new_number_list3 = filter(lambda x:x<ceiling, number_list)
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print('The following are numbers that are smaller than {0}: '.format(ceiling), list(new_number_list3))

‎py3_solution/exercises_4.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Create a program that asks the user for a number and then prints out a list of all the divisors of that number.
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(If you don’t know what a divisor is, it is a number that divides evenly into another number.
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For example, 13 is a divisor of 26 because 26 / 13 has no remainder.)
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'''
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n = input('Please input a number: ')
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n = int(n)
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# The simplest solution
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res = []
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for i in range(2, n):
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if n % i == 0:
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res.append(i)
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res.append(1)
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res.append(n)
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res.sort()
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print('The following are divisors of your input number: ')
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print(res)
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# A more efficient solution
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from math import sqrt
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x = int(sqrt(n))
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res2 = []
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for i in range(2, x):
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if n % i == 0:
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res2.append(i)
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res2.append(n//i)
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if n == x * x:
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res.append(x)
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res2.append(1)
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res2.append(n)
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res2.sort()
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print('The following are divisors of your input number calculated by another way: ')
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print(res2)

‎py3_solution/exercises_5.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Take two lists, say for example these two:
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a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
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b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
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and write a program that returns a list that contains only the elements that are common between the lists (without duplicates). Make sure your program works on two lists of different sizes.
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Extras:
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- Randomly generate two lists to test this
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- Write this in one line of Python (don’t worry if you can’t figure this out at this point - we’ll get to it soon)
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'''
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import random
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a = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
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b = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
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######################################
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# Randomly generate lists a and b
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######################################
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length1 = random.randint(10,20)
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a = [random.randint(1,50) for i in range(length1)]
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length2 = random.randint(10,20)
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b = [random.randint(1,50) for i in range(length2)]
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print('list a: ', a)
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print('list b: ', b)
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#######################################
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# Calculate intersection of a and b
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#######################################
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# method 1:
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res = []
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for i in a:
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if i in b:
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res.append(i)
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# Remove duplacates
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res = list(set(res))
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print('Method 1:')
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print('The intersection of a&b is: ', res)
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# method 2:
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res = filter(lambda x:x in b, a)
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res = list(set(res))
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print('Method 2:')
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print('The intersection of a&b is: ', res)
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# method 3:
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res = list(set(a) & set(b))
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print('Method 3:')
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print('The intersection of a&b is: ', res)
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‎py3_solution/exercises_6.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Ask the user for a string and print out whether this string is a palindrome or not.
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(A palindrome is a string that reads the same forwards and backwards.)
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'''
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word = input('Please input a string for check: ')
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# Method 1:
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reverse_word = word[::-1]
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if word == reverse_word:
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print('The word you input is a palindrome')
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else:
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print('The word you input is not a palindrome')
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# Method 2:
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is_palindrome = True
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length = len(word)
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for i in range(0, length//2):
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if word[i] != word[length-1-i]:
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is_palindrome = False
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break
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if is_palindrome:
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print('The word you input is a palindrome')
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else:
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print('The word you input is not a palindrome')

‎py3_solution/exercises_7.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Let’s say I give you a list saved in a variable: a = [1, 4, 9, 16, 25, 36, 49, 64, 81, 100].
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Write one line of Python that takes this list a and makes a new list that has only the even elements of this list in it.
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'''
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a = [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
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print('The target list is: ', a)
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b = [x for x in a if x%2==1]
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print('The new list that has only the even elements of previous list is: ')
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print(b)
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c = filter(lambda x:x%2!=0, a)
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print('The new list that has only the even elements of previous list is: ')
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print(list(c))

‎py3_solution/exercises_8.py‎

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#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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'''
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Make a two-player Rock-Paper-Scissors game.
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(Hint: Ask for player plays (using input), compare them, print out a message of congratulations to the winner, and ask if the players want to start a new game)
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Remember the rules:
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Rock beats scissors
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Scissors beats paper
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Paper beats rock
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'''
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rule = {
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'rock': 'paper',
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'paper': 'scissors',
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'scissors': 'rock'
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}
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results = {
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0: 'Same input',
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1: 'playerA wins!',
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2: 'playerB wins!'
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}
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def validate_input(val):
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if val in rule.keys():
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return True
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return False
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def valid_input_factory(player):
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val = input('Input for {0}: '.format(player)).lower()
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while not validate_input(val):
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print('Invalid input, input again...')
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val = input('Input for {0}: '.format(player)).lower()
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return val
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def compare(input_a, input_b):
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if input_a == input_b:
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result = 0
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elif rule[input_b] == input_a:
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result = 1
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else:
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result = 2
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return result
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def game():
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play_flag = 'yes'
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while not play_flag=='quit':
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print('Choices for input: rock, paper, scissors')
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input_a = valid_input_factory('playerA')
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input_b = valid_input_factory('playerB')
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print('player_A: {0}'.format(input_a), 'player_B: {0}'.format(input_b))
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res = compare(input_a, input_b)
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print(results[res])
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play_flag = input('Press <quit> to quit the game. \nPress any thing else to continue...')
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if __name__ == '__main__':
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game()
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