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Lottery3D.py
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Lottery3D.py
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# -*- coding: utf-8 -*-
''' ---------------------------------------
程序：Lottery3D.py
版本：Vincent © 1.0
作者：vincentlz
日期：2017/9/8 10:58
环境：Python 3.6 PyCharm
简介：
---------------------------------------
# code is far away from bugs with the god animal protecting
I love animals. They taste delicious.
┏┓ ┏┓
┏┛┻━━━┛┻┓
┃ ☃ ┃
┃ ┳┛ ┗┳ ┃
┃ ┻ ┃
┗━┓ ┏━┛
┃ ┗━━━┓
┃ 神兽保佑 ┣┓
┃ 永无BUG！ ┏┛
┗┓┓┏━┳┓┏┛
┃┫┫ ┃┫┫
┗┻┛ ┗┻┛'''
import urllib.request
import re
import xlwt
#定义一个函数，获取开奖页面html源码
def get_3d_html():
#生成页码列表，这里显示的是前12页的源码
page_num=range(1,14)
b=''
#循环获取
for page in page_num:
#通过分析链接页码拼接
url='http://kaijiang.zhcw.com/zhcw/html/3d/list_'+str(page_num[page-1])+'.html'
#打开链接
a=urllib.request.urlopen(url)
#读取
html=a.read()
#转码
html=html.decode('utf-8')
b=b+html
return b
# print(get_3d_html())
#构建正则提取需要的数据
def get_3d_num():
html=get_3d_html()
reg=re.compile(r'<tr>.*?<td align="center">'
r'(.*?)</td>.*?<td align="center">'
r'(.*?)</td>.*?<td align="center" '
r'style="padding-left:20px;">'
r'<em>(.*?)</em>.*?<em>(.*?)</em>.*?<em>(.*?)</em></td>',re.S)
it=re.findall(reg,html)
return it
# print(get_3d_num())
#定义excel函数，参数为get_3d_num()获取到的数据
def excel_create(ceshi):
newTable='fucai_3d.xls'
wb=xlwt.Workbook(encoding='utf-8')
ws=wb.add_sheet('test1')
headData=['开奖日期','期号','百位','十位','个位']
for col in range(0,5):
ws.write(0,col,headData[col])
index=1
for j in ceshi:
for i in range(0,5):
# print(j[i])
ws.write(index,i,j[i])
index +=1
wb.save(newTable)
if __name__=='__main__':
w=get_3d_num()
excel_create(w)
#最频繁出现概率最高的数字
def analyze_popu_nums(w):
import collections
all_nums=[]
bw_nums=[]
sw_nums=[]
gw_nums=[]
for each in w:
for n in each[-3:]:
all_nums.append(n)
bw_nums.append(each[2])
sw_nums.append(each[3])
gw_nums.append(each[4])
print('全年最火的三个数：',collections.Counter(all_nums).most_common(3))
print('百位最火的三个数：',collections.Counter(bw_nums).most_common(3))
print('十位最火的三个数：',collections.Counter(sw_nums).most_common(3))
print('个位最火的三个数：',collections.Counter(gw_nums).most_common(3))
print('-----------------------------------------------------------------')
#分析每期重复出现的数字概率，这个没理解清楚
def duplicat_num(w):
dup_count=0
for each in w:
if len(set(each[-3:]))<3:
dup_count += 1
print(dup_count)
dup_percet=round(dup_count/len(w),4)
print('duplicate num percent:{}%'.format(float(dup_percet)*100))
#最后记得要调用函数，不然没有分析数据
analyze_popu_nums(w)
duplicat_num(w)