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A368133
a(1,2,3) = 1,2,3; let j = a(n-1), M(n) = Product_{i = 1..n-2} { p a distinct prime: p | a(i), gcd(p, j) = 1 }. For n > 3, a(n) is the least novel multiple of M(n) if M(n) > 1; otherwise a(n) is the least novel multiple of A053669(j), the smallest prime which does not divide j.
3
1, 2, 3, 4, 6, 5, 12, 10, 9, 20, 15, 8, 30, 7, 60, 14, 45, 28, 75, 42, 25, 84, 35, 18, 70, 21, 40, 63, 50, 105, 16, 210, 11, 420, 22, 315, 44, 525, 66, 140, 33, 280, 99, 350, 132, 175, 198, 245, 264, 385, 24, 770, 27, 1540, 36, 1155, 26, 2310, 13, 4620, 39, 3080
OFFSET
1,2
COMMENTS
M(n) is a squarefree number whose prime factors are the distinct primes which divide a(m), m <= n-2, but do not divide j. M(n) > 1 implies there exists at least one term prior to j having a prime divisor which does not divide j, and M(n) is the product of all such primes. If, for any term a(m), m <= n-2, every prime factor of a(m) also divides j, then M(n) = 1, the empty product.
Primorial a(n-1) implies prime a(n); see Formula.
Conjectured to be a permutation of the positive integers.
Compare with A368108 which has a slightly different definition but works in a similar way.
From Michael De Vlieger, Jan 05 2024: (Start)
This sequence is the same as A362855 for 91306 terms.
A362855(91306) = a(91306) = A002110(17),
A362855(91307) = 53 = prime(16), a(91307) = 61 = prime(18),
A362855(91308) = A002110(17)/prime(16), a(91308) = 2*A002110(17).
Thereafter the sequences diverge. It seems unlikely that the 2 sequences will become coincident again as n increases beyond 91308. (End)
LINKS
Michael De Vlieger, Log log scatterplot of a(n) and b(n), n = 1..2^20, where a(n) is shown in red, b(n) = A362855(n) is shown in blue. Black indicates where a(n) = b(n).
FORMULA
When for some m, a(m) = A002110(n), a primorial number, a(m+1) = prime(n+1), a(m+2) = 2*A002110(n), and a(m+3) = 2*prime(n+1); see Example.
a(n) = A362855(n), for 1 <= n <= 91306 (see link and Example).
EXAMPLE
a(1, 2, 3) = 1, 2, 3. M(4) = 2 because 2 | a(2) but does not divide a(3); 2 is the only a(m), m < 3, with this property, so a(4) = 4, the least novel multiple of 2.
Now we have a(1,2,3,4) = 1,2,3,4. M(5) = 3 because 3 | a(3) but does not divide a(4); 3 is the only a(m), m < 4, with this property, so a(5) = 2*3 = 6, the least novel multiple of 3.
We now have a(1..5) = 1, 2, 3, 4, 6. M(6) = 1, the empty product, because there is no prime which divides some a(m), m < 5, which does not also divide a(n-1) = 6. This situation invokes the second condition of the definition, so a(6) = 1*5, the least novel multiple of A053669(6) = 5, the smallest prime which does not divide 6. Consequently a(7) = 2*6 = 12 because no prime dividing a(1..5) also divides 5.
The same situation arises again at a(13) = 30 = 2*3*5; every prime divisor of a(m), m < 13, is 2, 3, or 5, which again invokes the second condition, M(14) = 1, the empty product, so a(14) = 1*7, since A053669(30) = 7. Consequently a(15) = 2*7 = 14.
a(91307) = 61 (whereas A362855(91307) = 53; point of divergence from A362855).
MATHEMATICA
nn = 10^5; c[_] := False; m[_] := 1;
Array[Set[{a[#], c[#], m[#]}, {#, True, 2}] &, 3]; j = 3;
s = {2}; r = Max[s]; c[3] = False;
q[x_] := Block[{qq = 2}, While[Divisible[x, qq], qq = NextPrime[qq]]; qq];
Do[(If[# == 1,
Set[k, NextPrime[r]],
While[Or[c[#], # == j] &[# m[#]], m[#]++];
Set[k, # m[#]]] &[Times @@ Complement[s, #]];
s = Union[s, #];
If[Last[#] > r, r = Last[#]]) &@ FactorInteger[j][[All, 1]];
Set[{a[n], c[j], j}, {k, True, k}], {n, 4, nn}], n];
Array[a, nn] (* Michael De Vlieger, Jan 05 2024 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
EXTENSIONS
More terms from Michael De Vlieger, Jan 05 2024
STATUS
approved