OFFSET
0,5
FORMULA
T(2*n, n) = Sum_{k=0..n} CatalanNumber(n)^2 * binomial(n + k, k).
From Detlef Meya, Nov 22 2023: (Start)
T(n, k) = binomial(n, k)*binomial(n+1, k)*binomial(2*k, k)/(k+1)^2.
T(n, k) = A001263(n+1, k+1)*binomial(2*k, k)/(k+1). (End)
EXAMPLE
Triangle T(n, k) starts:
[0] 1;
[1] 1, 1;
[2] 1, 3, 2;
[3] 1, 6, 12, 5;
[4] 1, 10, 40, 50, 14;
[5] 1, 15, 100, 250, 210, 42;
[6] 1, 21, 210, 875, 1470, 882, 132;
[7] 1, 28, 392, 2450, 6860, 8232, 3696, 429;
[8] 1, 36, 672, 5880, 24696, 49392, 44352, 15444, 1430;
[9] 1, 45, 1080, 12600, 74088, 222264, 332640, 231660, 64350, 4862;
MAPLE
p := n -> hypergeom([1/2, -n - 1, -n], [2, 2], 4*x):
T := (n, k) -> coeff(simplify(p(n)), x, k):
seq(seq(T(n, k), k = 0..n), n = 0..9);
MATHEMATICA
T[n_, k_]:=Binomial[n, k]*Binomial[n+1, k]*Binomial[2*k, k]/(k+1)^2; Flatten[Table[T[n, k], {n, 0, 9}, {k, 0, n}]]
(* Detlef Meya, Nov 22 2023 *)
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Peter Luschny, Nov 06 2023
STATUS
approved