OFFSET
1,3
COMMENTS
Conjecture: For each k there exists a sufficiently large N, such that for all n > N, if p_1, p_2, ..., p_k are the k largest primes that divide a(n) then (p_1*p_2*...*p_k)^2 also divides a(n).
LINKS
Peter Kagey, Table of n, a(n) for n = 1..50
CROSSREFS
KEYWORD
nonn
AUTHOR
Peter Kagey, Feb 23 2022
STATUS
approved