OFFSET
1,2
COMMENTS
If p is prime, a(p) = Sum_{d|p} d^abs(mu(p/d)) = 1^1 + p^1 = p + 1.
FORMULA
a(8) = Sum_{d|8} d^abs(mu(8/d)) = 1^0 + 2^0 + 4^1 + 8^1 = 14.
MATHEMATICA
Table[Sum[k^Abs[MoebiusMu[n/k]] (1 - Ceiling[n/k] + Floor[n/k]), {k, n}], {n, 100}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Wesley Ivan Hurt, May 23 2021
STATUS
approved