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A341538
One of the two successive approximations up to 2^n for 2-adic integer sqrt(17). This is the 1 (mod 4) case.
7
1, 1, 9, 9, 41, 105, 233, 233, 745, 1769, 1769, 1769, 9961, 9961, 9961, 75497, 206569, 206569, 206569, 1255145, 1255145, 5449449, 13838057, 30615273, 64169705, 64169705, 64169705, 332605161, 869476073, 869476073, 869476073, 5164443369, 13754377961, 13754377961
OFFSET
2,3
COMMENTS
a(n) is the unique number k in [1, 2^n] and congruent to 1 mod 4 such that k^2 - 17 is divisible by 2^(n+1).
LINKS
FORMULA
a(2) = 1; for n >= 3, a(n) = a(n-1) if a(n-1)^2 - 17 is divisible by 2^(n+1), otherwise a(n-1) + 2^(n-1).
a(n) = 2^n - A341539(n).
a(n) = Sum_{i=0..n-1} A322217(i)*2^i.
EXAMPLE
The unique number k in [1, 4] and congruent to 1 modulo 4 such that k^2 - 17 is divisible by 8 is 1, so a(2) = 1.
a(2)^2 - 17 = -16 which is divisible by 16, so a(3) = a(2) = 1.
a(3)^2 - 17 = -16 which is not divisible by 32, so a(4) = a(3) + 2^3 = 9.
a(4)^2 - 17 = 64 which is divisible by 64, so a(5) = a(4) = 9.
a(5)^2 - 17 = 64 which is not divisible by 128, so a(6) = a(5) + 2^5 = 41.
...
PROG
(PARI) a(n) = truncate(sqrt(17+O(2^(n+1))))
CROSSREFS
Cf. A341539 (the 3 (mod 4) case), A322217 (digits of the associated 2-adic square root of 17), A318960, A318961 (successive approximations of sqrt(-7)).
Sequence in context: A097988 A103646 A246314 * A325895 A111219 A339341
KEYWORD
nonn
AUTHOR
Jianing Song, Feb 13 2021
STATUS
approved