%I #6 Jan 11 2021 23:35:17

%S 1,2,4,8,64,70,280,287,0,2,16,16,32,40,280,280,560,561,3366,3367,

%T 20202,20205,40410,40414,0,2,16,16,32,40,0,5,30,30,150,156,156,159,

%U 477,483,2898,2901,8703,8709,60963,60965,0,2,0,2,4,4,8,8,40,44,0,4,4,4

%N Similar to A100787, but alternate with addition and multiplication instead. See Comments section for more information.

%C We start with a(0) as 1, placing an addition sign below the digit. As such, we add 1 to a(0) to receive the next term which is 2. This time, place a multiplication sign below the new digit and double a(1) to receive a(2) which is 4. Place add under the next unused digit and add this to a(2), followed by multiply under the next a(3) and repeat.

%C Unlike A100787, terms within this sequence are not strictly increasing, as the 8th digit in this sequence is a 0 where we apply multiplication. Also, the differences do not reflect the digits of this sequence, due to alternation with multiplication. The records are 1, 2, 4, 8, 64, 70, 280, 287, 280, 560, 561, 3366 ...

%e 1, 2, 4, 8, 64, 70, 280, 287, 0, 2, 16, ...

%e + * + * +* +* +*+ *+* + * +*

%e To calculate a(5), we add 6 to 64, as the 5th digit is a 6 with the add operator underneath. Thus, a(5) is 70.

%e To calculate a(8), we multiply 287 by 0, as the 8th digit is a 0 with the multiply operator underneath. Thus, a(8) is 0.

%Y Cf. A100787, A107974, A107975, A107976, A107977.

%K base,nonn

%O 0,2

%A _Jamie Robert Creasey_, Dec 24 2020