OFFSET
1,2
COMMENTS
Conjectures:
1. This sequence consists only of 1's and primes.
2. Every odd prime of the form floor(sqrt(3)*m) greater than 3 is a term of this sequence.
3. At the first appearance of each prime of the form floor(sqrt(3)*m), it is larger than any prime that has already appeared.
The 2nd and 3rd conjectures are proved at the Mathematics Stack Exchange link. - Sungjin Kim, Jul 17 2019
LINKS
Michel Marcus, Table of n, a(n) for n = 1..10000
Mathematics Stack Exchange, Generating primes of the form floor(sqrt(3)*n)
PROG
(PARI) Generator(n)={b1=3; list=[]; for(k=2, n, b2=b1+lcm(floor(sqrt(3)*k), b1); a=b2/b1-1; list=concat(list, a); b1=b2); print(list)}
(PARI) lista(nn)={my(b1=3, b2, va=vector(nn)); for(k=2, nn+1, b2=b1+lcm(sqrtint(3*k^2), b1); va[k-1]=b2/b1-1; b1=b2); va}; \\ Michel Marcus, Aug 20 2022
CROSSREFS
KEYWORD
nonn
AUTHOR
Pedja Terzic, Jan 13 2019
STATUS
approved