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A282427
Numbers k such that A282442(k) = ceiling(k/2) + 1.
0
1, 3, 7, 39, 47, 111, 959, 3319, 7407, 11967, 13007, 16239
OFFSET
1,2
COMMENTS
All terms are odd.
Proof: if A282442(2m) = m + 1, then the step of length m would have to have concluded on exactly the middle step, but a phase with step-length m cannot end on the middle step because the distance from the middle step to the top/bottom of the staircase is equal to m.
LINKS
Mathematics Stack Exchange user Sheljohn, A curious sequence.
CROSSREFS
Cf. A282442.
Sequence in context: A373774 A169741 A335812 * A192198 A061931 A057203
KEYWORD
nonn,more
AUTHOR
Peter Kagey, Feb 15 2017
STATUS
approved