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Least positive odd number m such that numerator of zeta(-m) are divisible by A000928(n).
1

%I #15 Jan 19 2017 09:24:45

%S 31,43,57,67,23,21,129,61,83,163,99,83,19,155,87,291,279,185,99,199,

%T 381,125,239,365,195,129,93,291,399,85,269,221,51,89,21,591,521,19,

%U 427,79,235,47,223,407,627,31,11,377,289,513,259,731,219,329,543,743,101

%N Least positive odd number m such that numerator of zeta(-m) are divisible by A000928(n).

%H Seiichi Manyama, <a href="/A281246/b281246.txt">Table of n, a(n) for n = 1..150</a>

%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Herbrand%E2%80%93Ribet_theorem">Herbrand-Ribet theorem</a>

%e zeta(-11) = 691/32760 and 691 are divisible by A000928(47). So a(47) = 11.

%Y Cf. A000928, A001067.

%K nonn

%O 1,1

%A _Seiichi Manyama_, Jan 18 2017