OFFSET
1,2
COMMENTS
Conjectured to be a permutation of the natural numbers.
LINKS
Derek Orr, Table of n, a(n) for n = 1..10000
FORMULA
a(n) >= n^(1/3) for all n > 0. If a(n) = n^(1/3), then n is a cube. Note the converse is false: a(27) = 14.
PROG
(PARI) v=[]; k=1; while(#v<100, d=digits(k^3); D=digits(#v+1); if(#D<=#d, c=1; for(i=1, #D, if(D[i]!=d[i], c=0; break)); if(c&&!vecsearch(vecsort(v), k), v=concat(v, k); k=0)); k++); v
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Derek Orr, Jul 26 2015
STATUS
approved