OFFSET
1,1
COMMENTS
If two such numbers A050278(n_1)/(2^k_1*3^m_1) and A050278(n_2)/(2^k_2*3^m_2) are equal, then A050278(n_1) appears earlier than A050278(n_2) iff A050278(n_1)<A050278(n_2). For example, a(2)/(2^13*3^7)=a(3)/(2^7*3^11)= 77. There are 210189 such pairs.
Note that, a(1) = 2845310976 means that min(A050278(n)/(2^k*3^m)) = 2845310976/(2^19*3^4) = 67.
CROSSREFS
KEYWORD
nonn,base,fini
AUTHOR
Vladimir Shevelev and Peter J. C. Moses, May 12 2015
STATUS
approved