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A244351
Integers n such that for every integer k>0, n*6^k-1 has a divisor in the set { 7, 13, 31, 37, 97 }.
0
84687, 429127, 508122, 1273238, 1570311, 1656045, 2574762, 2847748, 3048732, 3345805, 3849481, 5076399, 5324003, 5338292, 5908351, 6961919, 7639428, 8167823, 8508662, 8994775, 9078721, 9421866, 9936270, 9950261
OFFSET
1,1
COMMENTS
For n > 24 a(n) = a(n-24) + 10124569, the first 24 values are in the data.
When the number a(n) has 1 or 6 as the last digit the number a(n)*6^k-1 is always divisible by 5 and have always a divisor in the set { 7, 13, 31, 37, 97 } for every k.
FORMULA
For n>24 a(n) = a(n-24) + 10124569.
KEYWORD
nonn
AUTHOR
Pierre CAMI, Jun 26 2014
STATUS
approved