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A236391
Positive numbers n such that 100*n^2/(100+n^2) are integers.
0
5, 10, 20, 30, 70
OFFSET
1,1
COMMENTS
Rewrite 100n^2/(100+n^2) as an I : n=sqrt(100I/(100-I)), where a finite substitution for I results.
Instead of 100, we could use 72 and get n=8,24,48,64; we could use 162 and get n=54,108,144,150. Many other values are possible.
EXAMPLE
for n=20, 100*20^2/(100+20^2)=I or 80.
MATHEMATICA
Select[Range[1000], IntegerQ[100*#^2/(100 + #^2)] &] (* T. D. Noe, Jan 29 2014 *)
CROSSREFS
Cf. A162688.
Sequence in context: A027884 A370532 A331141 * A026357 A117518 A107486
KEYWORD
nonn,fini,full
AUTHOR
Larry J Zimmermann, Jan 24 2014
STATUS
approved